0=49x^2+21x+2

Solution for 0=49x^2+21x+2 equation:

0=49x^2+21x+2

We move all terms to the left:

0-(49x^2+21x+2)=0

We add all the numbers together, and all the variables

-(49x^2+21x+2)=0

We get rid of parentheses

-49x^2-21x-2=0

a = -49; b = -21; c = -2;
Δ = b2-4ac
Δ = -212-4·(-49)·(-2)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-7}{2*-49}=\frac{14}{-98}
=-1/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+7}{2*-49}=\frac{28}{-98}
=-2/7
$